Question
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1. \( 2 x-5=3 \) 2. \( 4 x+6=x-3 \) 3. \( 5 a-3(a+1)=2-3 a \) 4. \( 2(x+2)=6(x+1)-(x-4) \)

Ask by Kelley Harris. in South Africa
Mar 09,2025

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Tutor-Verified Answer

Answer

1. \( x = 4 \) 2. \( x = -3 \) 3. \( a = 1 \) 4. \( x = -2 \)

Solution

1. Solve \(2x-5=3\): - Add \(5\) to both sides: \[ 2x = 3 + 5 = 8 \] - Divide both sides by \(2\): \[ x = \frac{8}{2} = 4 \] 2. Solve \(4x+6=x-3\): - Subtract \(x\) from both sides: \[ 3x + 6 = -3 \] - Subtract \(6\) from both sides: \[ 3x = -3 - 6 = -9 \] - Divide both sides by \(3\): \[ x = \frac{-9}{3} = -3 \] 3. Solve \(5a-3(a+1)=2-3a\): - Distribute the \(-3\) on the left: \[ 5a - 3a - 3 = 2 - 3a \] - Combine like terms on the left: \[ 2a - 3 = 2 - 3a \] - Add \(3a\) to both sides: \[ 2a + 3a - 3 = 2 \quad \Rightarrow \quad 5a - 3 = 2 \] - Add \(3\) to both sides: \[ 5a = 2 + 3 = 5 \] - Divide both sides by \(5\): \[ a = \frac{5}{5} = 1 \] 4. Solve \(2(x+2)=6(x+1)-(x-4)\): - Expand both sides: - Left-hand side: \[ 2(x+2)= 2x+4 \] - Right-hand side: \[ 6(x+1)-(x-4)=6x+6-x+4 = 5x+10 \] - Set the equation: \[ 2x+4 = 5x+10 \] - Subtract \(2x\) from both sides: \[ 4 = 3x+10 \] - Subtract \(10\) from both sides: \[ -6 = 3x \] - Divide both sides by \(3\): \[ x = \frac{-6}{3} = -2 \]

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Bonus Knowledge

To solve the first equation, \( 2x - 5 = 3 \), add 5 to both sides to get \( 2x = 8 \), then divide by 2 to find \( x = 4 \). For the second equation, \( 4x + 6 = x - 3 \), subtract \( x \) from both sides to have \( 3x + 6 = -3 \). Next, subtract 6 and divide by 3, yielding \( x = -3 \). In the third equation, \( 5a - 3(a + 1) = 2 - 3a \), distribute the -3 to get \( 5a - 3a - 3 = 2 - 3a \). Combine like terms: \( 2a - 3 = 2 - 3a \), then add \( 3a \) and \( 3 \) to find \( a = 1 \). Finally, for the fourth equation, \( 2(x + 2) = 6(x + 1) - (x - 4) \), distribute everything: \( 2x + 4 = 6x + 6 - x + 4 \). Combine the right side to \( 5x + 10 \), giving \( 2x + 4 = 5x + 10 \). Subtract \( 2x \) to get \( 4 = 3x + 10 \), then isolate \( x \) to find \( x = -2 \).

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