Question 8 of 10 ( 1 point) । Question Attempt: 1 of 1 Consider the line \( y=9 x-8 \). Find the equation of the line that is perpendicular to this line and passes through the point \( (5,-5) \). Find the equation of the line that is parallel to this line and passes through the point \( (5,-5) \). Note that the ALEKS graphing calculator may be helpful in checking your answer. Equation of parallel line:
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To find the equation of the line that is parallel to \( y = 9x - 8 \) and passes through the point \( (5, -5) \), we note that parallel lines have the same slope. The slope of the given line is \( 9 \). Using the point-slope form \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \( (x_1, y_1) = (5, -5) \): \[ y - (-5) = 9(x - 5) \\ y + 5 = 9x - 45 \\ y = 9x - 50 \] So, the equation of the parallel line is \( y = 9x - 50 \). **Equation of perpendicular line:** The slope of a line perpendicular to the given line is the negative reciprocal of \( 9 \), which is \( -\frac{1}{9} \). Using the same point, we have: \[ y - (-5) = -\frac{1}{9}(x - 5) \\ y + 5 = -\frac{1}{9}x + \frac{5}{9} \\ y = -\frac{1}{9}x + \frac{5}{9} - 5 \\ y = -\frac{1}{9}x - \frac{40}{9} \] Thus, the equation of the perpendicular line is \( y = -\frac{1}{9}x - \frac{40}{9} \).