Use ANNEXURE $$ A $$ and $$ B $$. 1.1.1 Drawline $$ B C $$ with point $$ C $$ on vertical line $$ riangle F $$, creating $$ A B C=30^{\circ} $$

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Use ANNEXURE $$ A $$ and $$ B $$. 1.1.1 Drawline $$ B C $$ with point $$ C $$ on vertical line $$ 	riangle F $$, creating $$ A B C=30^{\circ} $$

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1. Draw the vertical line corresponding to $$\triangle F$$. Label this line as $$\Delta F$$.

2. Choose a point $$B$$ (its exact location can be predetermined by context or given figures in Annexure $$A$$ or $$B$$).

3. Locate a point $$C$$ on the vertical line $$\Delta F$$.

4. Draw the line segment $$BC$$ joining point $$B$$ to point $$C$$.

5. At point $$B$$, construct an angle of $$30^\circ$$. To do this, use a protractor (or the construction means available in Annexure $$A$$ and $$B$$) to form the ray $$BA$$ such that  
   $$
   \angle ABC = 30^\circ.
   $$
   
6. Mark the point $$A$$ on the ray $$BA$$. The three points $$A$$, $$B$$, and $$C$$ now form $$\triangle ABC$$ with the angle at $$B$$ measuring $$30^\circ$$.
1. Draw the vertical line $$\Delta F$$. 2. Place point $$B$$ on this line. 3. Place point $$C$$ on the same vertical line. 4. Draw line $$BC$$ connecting $$B$$ and $$C$$. 5. At point $$B$$, create a $$30^\circ$$ angle to form ray $$BA$$. 6. Mark point $$A$$ on ray $$BA$$. Now, $$\triangle ABC$$ has $$\angle ABC = 30^\circ$$.

Use ANNEXURE \( A \) and \( B \). 1.1.1 Drawline \( B C \) with point \( C \) on vertical line \( \triangle F \), creating \( A B C=30^{\circ} \)

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