Question
dentify the terms of the expression. Then give the oefficient of each term. \( \begin{array}{ll}\text { 5. } 11 r+7 s & \text { 6. } 6 g-h\end{array} \)
Ask by Warner Lyons. in the United States
Mar 12,2025
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Answer
**Problem 5: \(11r + 7s\)**
- **Terms:** \(11r\), \(7s\)
- **Coefficients:** \(11\) (for \(11r\)), \(7\) (for \(7s\))
**Problem 6: \(6g - h\)**
- **Terms:** \(6g\), \(-h\)
- **Coefficients:** \(6\) (for \(6g\)), \(-1\) (for \(-h\))
Solution
**Problem 5: \(11r+7s\)**
1. The expression has two terms:
- The first term is \(11r\)
- The second term is \(7s\)
2. The coefficient of the first term \(11r\) is \(11\).
3. The coefficient of the second term \(7s\) is \(7\).
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**Problem 6: \(6g-h\)**
1. The expression has two terms (note that \(-h\) is considered as a term with an implied coefficient):
- The first term is \(6g\)
- The second term is \(-h\)
2. The coefficient of the first term \(6g\) is \(6\).
3. The coefficient of the second term \(-h\) is \(-1\) (since \(h\) is the same as \(1h\), the negative sign implies a coefficient of \(-1\)).
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Simplify this solution Bonus Knowledge
In the expression \(11r + 7s\), the terms are \(11r\) and \(7s\). The coefficient of the first term \(11r\) is 11, while the coefficient of the second term \(7s\) is 7. For the expression \(6g - h\), the terms are \(6g\) and \(-h\). Here, the coefficient of the first term \(6g\) is 6, while the coefficient of the second term \(-h\) is -1, since any variable without a number in front is understood to have a coefficient of 1 (and is negative in this case).
