Simplizy $$ \frac{4^{y}-2^{y+z}-8^{y}}{2^{2} \cdot 3^{0} \cdot 2^{3 y}} $$

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Calculate or simplify the expression $$ (4^y-2^{y+z}-8^y)/(2^2*3^0*2^(3*y)) $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\frac{\left(4^{y}-2^{y+z}-8^{y}ight)}{\left(2^{2}	imes 3^{0}	imes 2^{3y}ight)}$$
- step1: Evaluate the power:
  $$\frac{\left(4^{y}-2^{y+z}-8^{y}ight)}{\left(2^{2}	imes 1	imes 2^{3y}ight)}$$
- step2: Remove the parentheses:
  $$\frac{4^{y}-2^{y+z}-8^{y}}{2^{2}	imes 1	imes 2^{3y}}$$
- step3: Multiply the terms:
  $$\frac{4^{y}-2^{y+z}-8^{y}}{2^{3y+2}}$$
- step4: Factor the expression:
  $$\frac{2^{y}\left(2^{y}-2^{z}-2^{2y}ight)}{2^{3y+2}}$$
- step5: Reduce the fraction:
  $$\frac{2^{y}-2^{z}-2^{2y}}{2^{2y+2}}$$
The simplified form of the expression $$ \frac{4^{y}-2^{y+z}-8^{y}}{2^{2} \cdot 3^{0} \cdot 2^{3y}} $$ is $$ \frac{2^{y}-2^{z}-2^{2y}}{2^{2y+2}} $$.
The simplified form of the expression is $$ \frac{2^{y}-2^{z}-2^{2y}}{2^{2y+2}} $$.

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