\( 1 \leftarrow \) A tire is rotating 720 times per min. Through how many degrees does a point on the edge of the tire move in \( \frac{1}{2} \) sec? The point on the edge of the tire rotates \( \square^{\circ} \) in \( \frac{1}{2} \mathrm{sec} \). (Type an integer or a simplified fraction.)

To find out how many degrees a point on the edge of the tire moves in \( \frac{1}{2} \) second, we first determine the number of rotations per second. Given that the tire rotates 720 times per minute, we can convert this to rotations per second: \[ \frac{720 \text{ rotations}}{1 \text{ min}} \cdot \frac{1 \text{ min}}{60 \text{ sec}} = 12 \text{ rotations/sec} \] Next, we calculate how many rotations occur in \( \frac{1}{2} \) second: \[ 12 \text{ rotations/sec} \cdot \frac{1}{2} \text{ sec} = 6 \text{ rotations} \] Since each rotation corresponds to \( 360^\circ \), we now calculate the total degrees: \[ 6 \text{ rotations} \cdot 360^\circ/\text{rotation} = 2160^\circ \] Thus, the point on the edge of the tire rotates \( 2160^{\circ} \) in \( \frac{1}{2} \) second.