Given the demend equation \( \begin{array}{rl}P & P=-q_{d}^{2}-4 q_{d}+68 \text { and } \\ & P=-q_{s}^{2}-2 q_{s}+12 \text { Determine the } \\ & P_{s} \text { and } s\end{array} \)
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The Deep Dive
To solve for \( P_s \) and \( s \), we can set the demand equation equal to the supply equation since, at equilibrium, quantity demanded equals quantity supplied (\( q_d = q_s = s \)). Given the equations: 1. Demand: \( P = -q_d^2 - 4q_d + 68 \) 2. Supply: \( P = -q_s^2 - 2q_s + 12 \) We can set both equations equal to each other: \[ -q_s^2 - 4q_s + 68 = -q_s^2 - 2q_s + 12 \] We can simplify this equation by eliminating \( -q_s^2 \) from both sides: \[ -4q_s + 68 = -2q_s + 12 \] Now, isolate the terms involving \( q_s \) on one side and constants on the other: \[ -4q_s + 2q_s = 12 - 68 \] This simplifies to: \[ -2q_s = -56 \] Dividing both sides by -2 gives: \[ q_s = 28 \] Since \( q_d = q_s \) at equilibrium, we have \( s = 28 \). Now, we can find \( P_s \) by substituting \( q_s = 28 \) back into either original equation. We'll use the supply equation: \[ P_s = -28^2 - 2(28) + 12 \] Calculating: \[ P_s = -784 - 56 + 12 \] \[ P_s = -784 - 44 \] \[ P_s = -828 \] Thus, at equilibrium \( P_s = -828 \) and \( s = 28 \).