Solve using elimination, \[ \begin{array}{l}-8 x-6 y=12 \\ -6 x-6 y=18\end{array} \]

Solve the system of equations \( -8x-6y=12;-6x-6y=18 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}-8x-6y=12\\-6x-6y=18\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}x=-\frac{6+3y}{4}\\-6x-6y=18\end{array}\right.\) - step2: Substitute the value of \(x:\) \(-6\left(-\frac{6+3y}{4}\right)-6y=18\) - step3: Multiply the terms: \(\frac{3\left(6+3y\right)}{2}-6y=18\) - step4: Multiply both sides of the equation by LCD: \(\left(\frac{3\left(6+3y\right)}{2}-6y\right)\times 2=18\times 2\) - step5: Simplify the equation: \(18-3y=36\) - step6: Move the constant to the right side: \(-3y=36-18\) - step7: Subtract the numbers: \(-3y=18\) - step8: Change the signs: \(3y=-18\) - step9: Divide both sides: \(\frac{3y}{3}=\frac{-18}{3}\) - step10: Divide the numbers: \(y=-6\) - step11: Substitute the value of \(y:\) \(x=-\frac{6+3\left(-6\right)}{4}\) - step12: Substitute back: \(x=\frac{-6+3\times 6}{4}\) - step13: Calculate: \(x=3\) - step14: Calculate: \(\left\{ \begin{array}{l}x=3\\y=-6\end{array}\right.\) - step15: Check the solution: \(\left\{ \begin{array}{l}x=3\\y=-6\end{array}\right.\) - step16: Rewrite: \(\left(x,y\right) = \left(3,-6\right)\) The solution to the system of equations using elimination is \( (x,y) = (3,-6) \).