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\( 2 x y^{2} \) when \( x=6 \) and \( y=-4 \)

Ask by Bartlett Bowers. in the United States
Mar 15,2025

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When \( x = 6 \) and \( y = -4 \), \( 2xy^2 = 192 \).

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Let’s plug in those values! First, substitute \( x \) and \( y \) into the expression \( 2xy^{2} \). So, \( 2(6)(-4)^{2} \). Calculating \( (-4)^{2} \) gives us \( 16 \). Now, multiply it all together: \( 2 \times 6 \times 16 = 192 \). The final result is \( 192 \).

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