Answer
The function \( f(x) = \frac{7}{-x^{2}-8} \) has a horizontal asymptote at \( y = 0 \) and no vertical asymptotes.
Solution
Function by following steps:
- step0: Find the horizontal asymptotes:
\(f\left(x\right)=\frac{7}{-x^{2}-8}\)
- step1: Evaluate the limits \(\lim _{x\rightarrow +\infty}\left(f\left(x\right)\right)\) and \(\lim _{x\rightarrow -\infty}\left(f\left(x\right)\right):\)
\(\begin{align}&\lim _{x\rightarrow +\infty}\left(\frac{7}{-x^{2}-8}\right)\\&\lim _{x\rightarrow -\infty}\left(\frac{7}{-x^{2}-8}\right)\end{align}\)
- step2: Calculate:
\(\begin{align}&0\\&0\end{align}\)
- step3: The finite values are horizontal asymptotes:
\(\begin{align}&f\left(x\right)=0\end{align}\)
Find the vertical asymptotes of \( f(x)=\frac{7}{-x^{2}-8} \).
Function by following steps:
- step0: Find the vertical asymptotes:
\(f\left(x\right)=\frac{7}{-x^{2}-8}\)
- step1: The function has no vertical asymptote:
\(\textrm{No vertical asymptotes}\)
To analyze the rational function
\[
f(x) = \frac{7}{-x^{2}-8}
\]
we can determine the asymptotes as follows:
1. **Horizontal Asymptotes:**
- The horizontal asymptote is found by examining the behavior of \( f(x) \) as \( x \) approaches infinity or negative infinity.
- In this case, as \( x \to \pm \infty \), the term \(-x^2\) dominates the denominator, leading to:
\[
f(x) \to \frac{7}{-\infty} = 0
\]
- Therefore, the horizontal asymptote is:
\[
y = 0
\]
2. **Vertical Asymptotes:**
- Vertical asymptotes occur where the denominator is zero and the numerator is not zero.
- Setting the denominator equal to zero:
\[
-x^2 - 8 = 0 \implies -x^2 = 8 \implies x^2 = -8
\]
- Since \( x^2 = -8 \) has no real solutions, there are no vertical asymptotes.
### Summary of Asymptotes:
- **Horizontal Asymptote:** \( y = 0 \)
- **Vertical Asymptotes:** None
You can graph the function and include the horizontal line \( y = 0 \) to represent the horizontal asymptote. There are no vertical lines to graph since there are no vertical asymptotes.
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