What value of \( s \) is a solution to this equation? \( \begin{array}{l}3-6 s=3 s+48 \\ s=-7 \\ s=-5\end{array} \)

Solve the equation \( 3-6s=3s+48 \). Solve the equation by following steps: - step0: Solve for \(s\): \(3-6s=3s+48\) - step1: Move the variable to the left side: \(3-6s-3s=48\) - step2: Subtract the terms: \(3-9s=48\) - step3: Move the constant to the right side: \(-9s=48-3\) - step4: Subtract the numbers: \(-9s=45\) - step5: Change the signs: \(9s=-45\) - step6: Divide both sides: \(\frac{9s}{9}=\frac{-45}{9}\) - step7: Divide the numbers: \(s=-5\) The value of \( s \) that is a solution to the equation is \( s = -5 \).