Question
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b) The sum of two numbers is 39 . If the greater number is 5 more than the orget one, find the numbers. The sum of two numbers is 54 . If the smaller number is 6 less than thee geser one, find the numbers.

Ask by Reyes Love. in Nepal
Feb 18,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The numbers are 22 and 17 for the first part, and 30 and 24 for the second part.

Solution

Let's break down the two parts of the problem step by step. ### Part 1: The sum of two numbers is 39 1. **Define the variables:** - Let \( x \) be the greater number. - Let \( y \) be the smaller number. 2. **Set up the equations based on the problem statement:** - From the first condition, we have: \[ x + y = 39 \quad (1) \] - From the second condition, we know that the greater number is 5 more than the smaller number: \[ x = y + 5 \quad (2) \] 3. **Substitute equation (2) into equation (1):** \[ (y + 5) + y = 39 \] Simplifying this gives: \[ 2y + 5 = 39 \] \[ 2y = 39 - 5 \] \[ 2y = 34 \] \[ y = 17 \] 4. **Find \( x \) using equation (2):** \[ x = y + 5 = 17 + 5 = 22 \] So, the two numbers are \( 22 \) (greater) and \( 17 \) (smaller). ### Part 2: The sum of two numbers is 54 1. **Define the variables:** - Let \( a \) be the greater number. - Let \( b \) be the smaller number. 2. **Set up the equations based on the problem statement:** - From the first condition, we have: \[ a + b = 54 \quad (3) \] - From the second condition, we know that the smaller number is 6 less than the greater number: \[ b = a - 6 \quad (4) \] 3. **Substitute equation (4) into equation (3):** \[ a + (a - 6) = 54 \] Simplifying this gives: \[ 2a - 6 = 54 \] \[ 2a = 54 + 6 \] \[ 2a = 60 \] \[ a = 30 \] 4. **Find \( b \) using equation (4):** \[ b = a - 6 = 30 - 6 = 24 \] So, the two numbers are \( 30 \) (greater) and \( 24 \) (smaller). ### Summary of Results: - For the first part, the numbers are \( 22 \) and \( 17 \). - For the second part, the numbers are \( 30 \) and \( 24 \).

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To solve the first problem, let's denote the greater number as \( x \) and the smaller number as \( y \). We know from the problem that \( x + y = 39 \) and \( x = y + 5 \). By substituting \( x \) in the first equation, we get \( (y + 5) + y = 39 \). Solving for \( y \) gives us \( 2y + 5 = 39 \), leading to \( 2y = 34 \), so \( y = 17 \). Substituting back, \( x = 22 \). Thus, the numbers are 22 and 17. For the second problem, let’s again denote the larger number as \( x \) and the smaller as \( y \). The equations we have are \( x + y = 54 \) and \( y = x - 6 \). By substituting \( y \) into the first equation: \( x + (x - 6) = 54 \) gives \( 2x - 6 = 54 \). Solving for \( x \), we have \( 2x = 60 \) which leads to \( x = 30 \). Then substituting back, \( y = 24 \). Thus, the numbers are 30 and 24.

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