The polynomial of degree \( 5, P(x) \) has leading coefficient 1 , has roots of multiplicity 2 at \( x=2 \) and \( x=0 \) and a root of multiplicity 1 at \( x=-5 \) Find a possible formula for \( P(x) \). \( P(x)= \)
Upstudy AI Solution
Answer
Solution
Answered by UpStudy AI and reviewed by a Professional Tutor


The Deep Dive
To find the polynomial \( P(x) \), we start with the given roots and their multiplicities. The root at \( x=2 \) has multiplicity 2, meaning it contributes the factor \( (x-2)^2 \). The root at \( x=0 \) also has multiplicity 2, contributing the factor \( x^2 \). Lastly, the root at \( x=-5 \) has multiplicity 1, contributing the factor \( (x+5) \). Putting it all together, the polynomial can be expressed as: \[ P(x) = (x-2)^2 \cdot x^2 \cdot (x+5) \] Expanding this gives: 1. First, expand \( (x-2)^2 \): \[ (x-2)^2 = x^2 - 4x + 4 \] 2. Combine this with \( x^2 \): \[ (x^2 - 4x + 4)x^2 = x^4 - 4x^3 + 4x^2 \] 3. Now multiply this by \( (x + 5) \): \[ (x^4 - 4x^3 + 4x^2)(x + 5) = x^5 + 5x^4 - 4x^4 - 20x^3 + 4x^3 + 20x^2 \] 4. Combine like terms: \[ P(x) = x^5 + (5 - 4)x^4 + (-20 + 4)x^3 + 20x^2 = x^5 + x^4 - 16x^3 + 20x^2 \] Thus, the complete polynomial is: \[ P(x) = x^5 + x^4 - 16x^3 + 20x^2 \]