Question
Fill in the blanks to describe the graph of the quadratic function, \( y=-\frac{1}{6} x^{2}-x+8 \). The parabola opens \( [?] \), and its shape is \( \quad \) than \( y=x^{2} \). downward
Ask by Park Ayala. in the United States
Jan 22,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The parabola opens downward and is wider than \( y = x^{2} \).
Solution
The quadratic function \( y = -\frac{1}{6}x^{2} - x + 8 \) can be described by filling in the blanks as follows:
- **The parabola opens** **downward**, **and its shape is** **wider** **than** \( y = x^{2} \).
**Explanation:**
1. **Direction the Parabola Opens:**
- The coefficient of \( x^{2} \) is \( -\frac{1}{6} \), which is negative.
- A negative coefficient indicates that the parabola opens **downward**.
2. **Shape Comparison to \( y = x^{2} \):**
- The coefficient \( -\frac{1}{6} \) has an absolute value less than 1.
- When the absolute value of the coefficient \( |a| < 1 \), the parabola is **wider** compared to the standard parabola \( y = x^{2} \).
- This means it spreads out more, making it less steep.
**Final Description:**
The parabola opens **downward**, and its shape is **wider** than \( y = x^{2} \).
Answered by UpStudy AI and reviewed by a Professional Tutor
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Beyond the Answer
The parabola opens downward, and its shape is wider than \( y=x^{2} \). This is because the coefficient of \( x^2 \) in the equation is negative and quite small in absolute value (specifically, \(-\frac{1}{6}\)), which means it stretches out more horizontally compared to the standard parabola \( y=x^2 \). So, you can say this graph is a broader, more relaxed version of the typical parabola!