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16 For maximum benefil during exercise, one's heart rate should increase by \( 50 \% \) to \( 85 \% \) above resting heart rate. (a) For a woman with a resting heart rate of 76 bpm , what would her heart rate be if she increased it by \( 75 \% \) during exercise? (b) A man with a resting heart rate of 88 bpm increased it to 132 bpm during exercise. By what percent did he increase his resting heart rate? (a) The woman's heart rate would be 133 bpm (Type a whole number or an exact decimal. If the decimal does not terminate, round to the nearest whole number.) (b) The man increased his resting heart rate by \( \square \% \). (Type a whole number or an exact decimal. If the decimal does not terminate, round to the nearest whole number.)

Ask by Wang Hammond. in the United States
Jan 14,2025

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**(b)** The man increased his resting heart rate by **50%**.

Solution

**(b)** The man's resting heart rate increased by \( 50\% \). **Explanation:** To find the percentage increase in the man's heart rate: 1. **Identify the original and new heart rates:** - **Original (resting) heart rate:** 88 bpm - **New heart rate during exercise:** 132 bpm 2. **Calculate the difference:** \[ 132 \, \text{bpm} - 88 \, \text{bpm} = 44 \, \text{bpm} \] 3. **Compute the percentage increase:** \[ \left( \frac{44}{88} \right) \times 100\% = 50\% \] So, the man increased his resting heart rate by **50%** during exercise. **Answer:** (b) The man increased his resting heart rate by 50 %.

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To solve the questions, we’ll first break down each part. (a) To find the woman's heart rate after increasing it by \( 75 \% \): - First, calculate \( 75 \% \) of her resting heart rate: \( 75 \% \) of \( 76 \text{ bpm} \) equals \( 0.75 \times 76 = 57 \text{ bpm} \). - Then, add this to her resting heart rate: \( 76 \text{ bpm} + 57 \text{ bpm} = 133 \text{ bpm} \). So, her heart rate during exercise would be **133 bpm**. (b) To find the percentage increase in the man's heart rate: - First, find the increase in heart rate: \( 132 \text{ bpm} - 88 \text{ bpm} = 44 \text{ bpm} \). - Then, calculate the percentage increase relative to his resting heart rate: \(\frac{44}{88} \times 100 = 50 \%\). So, the man increased his resting heart rate by **50%**.

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