\begin{tabular}{l} 11) Solve the problem. \ $$ \qquad \frac{7}{8}-\frac{6}{7}=\square $$ \ \hline$$ \frac{1}{1} $$\end{tabular}

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1. Write the subtraction with a common denominator. The denominators $$8$$ and $$7$$ have a least common denominator (LCD) of $$56$$.

2. Convert each fraction:
   - $$\frac{7}{8} = \frac{7 \times 7}{8 \times 7} = \frac{49}{56}$$
   - $$\frac{6}{7} = \frac{6 \times 8}{7 \times 8} = \frac{48}{56}$$

3. Subtract the fractions:
   $$
   \frac{49}{56} - \frac{48}{56} = \frac{49 - 48}{56} = \frac{1}{56}
   $$

Thus, the answer is $$ \boxed{\frac{1}{56}} $$.
The answer is $$ \frac{1}{56} $$.

\begin{tabular}{l} 11) Solve the problem. \\ \( \qquad \frac{7}{8}-\frac{6}{7}=\square \) \\ \hline\( \frac{1}{1} \)\end{tabular}

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