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13. A group of students attend a math club. Half of the students are boys and \( \frac{4}{9} \) of the boys have brown eyes. What fraction of the group are boys with brown eyes?

Ask by Delgado May. in the United States
Mar 09,2025

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Answer

The fraction of the group that are boys with brown eyes is \( \frac{2}{9} \).

Solution

Let the total number of students be \( N \). 1. Since half of the students are boys, the number of boys is: \[ \frac{1}{2}N \] 2. Given that \( \frac{4}{9} \) of these boys have brown eyes, the number of boys with brown eyes is: \[ \frac{4}{9} \times \frac{1}{2}N = \frac{4}{18}N = \frac{2}{9}N \] 3. Therefore, the fraction of the group that are boys with brown eyes is: \[ \frac{2}{9} \]

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Let's break it down! If half of the students are boys, then the number of boys is \( \frac{1}{2} \) of the total group. If we denote the total number of students as \( S \), the number of boys would be \( \frac{S}{2} \). Now, \( \frac{4}{9} \) of the boys have brown eyes. To find the number of boys with brown eyes, we multiply the total number of boys by \( \frac{4}{9} \). This gives us: \[ \text{Boys with brown eyes} = \frac{4}{9} \times \frac{S}{2} = \frac{4S}{18} = \frac{2S}{9} \] To find the fraction of the entire group that these boys represent, we divide the number of boys with brown eyes by the total number of students: \[ \text{Fraction of the group that are boys with brown eyes} = \frac{\frac{2S}{9}}{S} = \frac{2}{9} \] So, the final answer is \( \frac{2}{9} \).

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