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(b) \( \frac{1}{(3+2 \sqrt{2})} \)

Ask by Daniel Nichols. in India
Jan 30,2025

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Answer

The simplified form is \( 3 - 2\sqrt{2} \).

Solution

To simplify the expression \( \frac{1}{3 + 2\sqrt{2}} \), we can rationalize the denominator. This involves eliminating the square root from the denominator by multiplying both the numerator and the denominator by the conjugate of the denominator. **Step-by-Step Solution:** 1. **Identify the Conjugate:** The conjugate of \( 3 + 2\sqrt{2} \) is \( 3 - 2\sqrt{2} \). 2. **Multiply Numerator and Denominator by the Conjugate:** \[ \frac{1}{3 + 2\sqrt{2}} \times \frac{3 - 2\sqrt{2}}{3 - 2\sqrt{2}} = \frac{3 - 2\sqrt{2}}{(3 + 2\sqrt{2})(3 - 2\sqrt{2})} \] 3. **Simplify the Denominator:** Use the difference of squares formula \( (a + b)(a - b) = a^2 - b^2 \): \[ (3)^2 - (2\sqrt{2})^2 = 9 - 8 = 1 \] 4. **Final Simplification:** \[ \frac{3 - 2\sqrt{2}}{1} = 3 - 2\sqrt{2} \] **Conclusion:** The simplified form of \( \frac{1}{3 + 2\sqrt{2}} \) is: \[ 3 - 2\sqrt{2} \]

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To simplify \( \frac{1}{3 + 2 \sqrt{2}} \), you can multiply the numerator and the denominator by the conjugate of the denominator, \( 3 - 2 \sqrt{2} \). This will help eliminate the square root in the denominator. Thus, we get: \[ \frac{1 \cdot (3 - 2\sqrt{2})}{(3 + 2\sqrt{2})(3 - 2\sqrt{2})} = \frac{3 - 2\sqrt{2}}{3^2 - (2\sqrt{2})^2} = \frac{3 - 2\sqrt{2}}{9 - 8} = 3 - 2\sqrt{2}. \] So the simplified expression is \( 3 - 2\sqrt{2} \). The next time you encounter such expressions, remember that multiplying by the conjugate is a handy trick to simplify fractions with square roots! It’s not just about making it look nicer; you’re also making it easier to work with in equations or further calculations. To truly master rationalizing denominators, try practicing with various expressions. Grab a couple of examples with different combinations of terms, like \( \frac{1}{5 - \sqrt{3}} \) or \( \frac{1}{2 + \sqrt{7}} \) and see how they work out. The more you practice, the easier and quicker it becomes!

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