The volume of the solid is or approximately 53.617 cubic units.
Solution
We first express the curve in a form that makes it easy to use the disk method. The region is bounded by
Since the curve is given as , we solve for to express the boundary in terms of :
When we revolve the region about the -axis, for a fixed the horizontal slice runs from to . This slice, when revolved about the -axis, forms a disk (since the inner radius is zero) with
The area of one such disk is
The -values range from the bottom of the region up to the top where the curve meets the -axis. When , the curve gives
Thus, the limits for are and .
The volume of the solid is then given by
We next expand the integrand:
So the volume integral becomes
Now, we integrate term by term:
Putting everything together:
To combine these terms, we use a common denominator, which is :
Thus,
So, the volume is
Now, rounding to the nearest thousandth, we approximate:
Thus, the volume of the solid is
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Beyond the Answer
To find the volume of the solid formed by revolving the region bounded by , , and about the -axis using the disk method, we first need to express in terms of .
The equation can be rearranged to find :
Next, we need to establish the limits for . The function crosses the -axis when , giving . The volume can be computed using the disk method, where the volume is given by the integral:
Now we calculate the integral:
First, expand the integrand:
Rewrite the volume integral:
Now, calculate the integral:
Plug in the limits:
To combine these fractions, find a common denominator:
The least common multiple of 3 and 5 is 15. Therefore, we express each term with a denominator of 15:
Combine the terms:
Now we compute the final volume:
Numerical approximation:
Rounding to the nearest thousandth, the final volume is: