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Determine the domain of the function. \( f(x)=\sqrt{7-x} \) Choose the domain of \( f(x) \). A. \( [7, \infty) \) B. \( (-\infty, \infty) \) C. \( (-\infty, 7] \) D. \( (-\infty, 7) \)

Ask by Barker Powell. in the United States
Mar 08,2025

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Answer

The domain of \( f(x) = \sqrt{7 - x} \) is all real numbers less than or equal to 7, which is \( (-\infty, 7] \).

Solution

We have the function \( f(x)=\sqrt{7-x} \). 1. The square root is defined when the expression under the square root is non-negative, so we need: \[ 7-x \geq 0. \] 2. Solving the inequality: \[ 7-x \geq 0 \quad \Longrightarrow \quad -x \geq -7 \quad \Longrightarrow \quad x \leq 7. \] (Multiplying both sides by \(-1\) reverses the inequality.) 3. Thus, the domain of \( f(x) \) is the set of all real numbers \( x \) such that \( x \leq 7 \). In interval notation, this is: \[ (-\infty, 7]. \] Therefore, the correct answer is C. \( (-\infty, 7] \).

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Bonus Knowledge

To determine the domain of the function \( f(x) = \sqrt{7 - x} \), we need to ensure that the expression under the square root is non-negative. This means we must have \( 7 - x \geq 0 \), which simplifies to \( x \leq 7 \). Thus, the domain of \( f(x) \) is all values of \( x \) that are less than or equal to 7. Hence, the correct answer is C. \( (-\infty, 7] \). Remember that with square root functions, the radicand (the expression inside the square root) must always be greater than or equal to zero for the function to produce real number outputs.

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