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Answer
When \( d = -8 \), the expression \( -d^+ + (-9) \) equals \(-9\).
Solution
Let \( d = -8 \).
1. First, we interpret \( d^+ \) as the positive part of \( d \), defined by:
\[
d^+ = \max\{d, 0\}
\]
2. Substitute \( d = -8 \):
\[
(-8)^+ = \max\{-8, 0\} = 0
\]
3. Now, substitute \( d^+ = 0 \) into the expression:
\[
-d^+ + (-9) = -0 - 9 = -9
\]
Thus, the evaluated expression is \(\boxed{-9}\).
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Simplify this solution Mind Expander
To evaluate \( -d^{+}+(-9) \) when \( d=-8 \), we first need to determine \( d^{+} \). The notation \( d^{+} \) usually signifies the positive part of \( d \), which for negative numbers is 0. Therefore, \( d^{+} = 0 \). Now we can substitute \( d^{+} \) into the expression: \[ -d^{+} + (-9) = -0 + (-9) = 0 - 9 = -9 \] So, the result of the evaluation is: \[ \boxed{-9} \]
