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\( \frac{-2}{5}, \frac{2}{3}, \frac{7}{15} \), 20. Solve \( :\left\{\left(3^{3}\right)^{2} \times 3^{3} \div 3^{7}\right\}+3^{0} \)

Ask by Clark Cook. in India
Feb 20,2025

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Answer

The answer is 10.

Solution

Calculate or simplify the expression \( (3^3)^2 * 3^3 / 3^7 + 3^0 \). Calculate the value by following steps: - step0: Calculate: \(\frac{\left(3^{3}\right)^{2}\times 3^{3}}{3^{7}}+3^{0}\) - step1: Evaluate the power: \(\frac{\left(3^{3}\right)^{2}\times 3^{3}}{3^{7}}+1\) - step2: Multiply by \(a^{-n}:\) \(\left(3^{3}\right)^{2}\times 3^{3}\times 3^{-7}+1\) - step3: Multiply the exponents: \(3^{3\times 2}\times 3^{3}\times 3^{-7}+1\) - step4: Multiply the numbers: \(3^{6}\times 3^{3}\times 3^{-7}+1\) - step5: Multiply: \(3^{2}+1\) - step6: Evaluate the power: \(9+1\) - step7: Add the numbers: \(10\) The solution to the expression \( \left\{\left(3^{3}\right)^{2} \times 3^{3} \div 3^{7}\right\}+3^{0} \) is 10.

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First, let’s simplify the expression step by step. Start with the nested expression: \((3^3)^2\) simplifies to \(3^{3 \times 2} = 3^6\). Now substitute back into the original equation: \[ \left\{3^6 \times 3^3 \div 3^7\right\} \] Using the laws of exponents, we can combine the multiplication first: \(3^6 \times 3^3 = 3^{6 + 3} = 3^9\). Next, divide by \(3^7\): \[ 3^9 \div 3^7 = 3^{9 - 7} = 3^2 \] Now, simplify \(3^2 = 9\). Don't forget about the \(+3^0\), which equals \(1\): So, we add: \[9 + 1 = 10.\] The final answer is: \[ \boxed{10}. \]

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