Factor the trinomial, or state that the trinomial is prime. Select the correct choice below and fill in any answer boxes within your choice. A. \( x^{2}-3 x-18 \) B. The polynomial is prime.

1. We have the trinomial \[ x^2 - 3x - 18. \] 2. We need to find two numbers that multiply to \(-18\) (the product of the coefficient of \( x^2 \) and the constant term) and add up to \(-3\) (the coefficient of \( x \)). The numbers \(3\) and \(-6\) satisfy these conditions since \(3 \times (-6) = -18\) and \(3 + (-6) = -3\). 3. Using these numbers, we factor the trinomial as: \[ (x + 3)(x - 6). \] 4. Therefore, the correct choice is A, and the factorization is: \[ x^{2} - 3x - 18 = (x + 3)(x - 6). \]