Question
upstudy study bank question image url

QUESTION I Parabola - The graph of the form \( f(x)=a(x+p)^{2}+q \) 1.1 Draw the graphs of the equations below accorting to the Graph Papers indicated: First Graph Paper Original graph (M): \( y=x^{2} \) Graph 1: \( y=2 r^{2} \) Graph 2: \( y=\frac{1}{2} x^{2} \) Graph 3: \( y=-2 r^{2} \) Second Graph Paper Original graph (M):y= \( x^{2} \) Graph 1: \( y=x^{2}-4 \) Graph 2: \( y=x^{2}+2 \) Graph 3: \( y=2 r^{2}-4 \) Graph 4: \( y=\frac{1}{2} x^{2}+2 \)

Ask by Stephens Mejia. in South Africa
Feb 21,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

To graph the given equations: 1. **First Graph Paper:** - **Original Graph (M):** \( y = x^2 \) (standard upward-opening parabola) - **Graph 1:** \( y = 2x^2 \) (steeper upward-opening parabola) - **Graph 2:** \( y = \frac{1}{2}x^2 \) (less steep upward-opening parabola) - **Graph 3:** \( y = -2x^2 \) (downward-opening parabola) 2. **Second Graph Paper:** - **Original Graph (M):** \( y = x^2 \) (standard upward-opening parabola) - **Graph 1:** \( y = x^2 - 4 \) (downward-shifted parabola) - **Graph 2:** \( y = x^2 + 2 \) (upward-shifted parabola) - **Graph 3:** \( y = 2x^2 - 4 \) (stretched and downward-shifted parabola) - **Graph 4:** \( y = \frac{1}{2}x^2 + 2 \) (compressed and upward-shifted parabola) Each graph is a transformation of the original \( y = x^2 \) parabola, involving vertical stretches, compressions, and shifts.

Solution

To draw the graphs of the given equations, we will analyze each equation step by step. The original graph is \( y = x^2 \), which is a standard parabola opening upwards with its vertex at the origin (0,0). ### First Graph Paper 1. **Original Graph (M):** - Equation: \( y = x^2 \) - This is a standard parabola. 2. **Graph 1:** - Equation: \( y = 2x^2 \) - This graph is a vertical stretch of the original graph by a factor of 2. The vertex remains at (0,0), but the parabola opens upwards more steeply. 3. **Graph 2:** - Equation: \( y = \frac{1}{2}x^2 \) - This graph is a vertical compression of the original graph by a factor of 0.5. The vertex remains at (0,0), but the parabola opens upwards less steeply. 4. **Graph 3:** - Equation: \( y = -2x^2 \) - This graph is a vertical stretch of the original graph by a factor of 2, but it opens downwards. The vertex remains at (0,0). ### Second Graph Paper 1. **Original Graph (M):** - Equation: \( y = x^2 \) - This is the same standard parabola as before. 2. **Graph 1:** - Equation: \( y = x^2 - 4 \) - This graph is a downward shift of the original graph by 4 units. The vertex moves from (0,0) to (0,-4). 3. **Graph 2:** - Equation: \( y = x^2 + 2 \) - This graph is an upward shift of the original graph by 2 units. The vertex moves from (0,0) to (0,2). 4. **Graph 3:** - Equation: \( y = 2x^2 - 4 \) - This graph is a vertical stretch of the original graph by a factor of 2 and a downward shift by 4 units. The vertex moves from (0,0) to (0,-4). 5. **Graph 4:** - Equation: \( y = \frac{1}{2}x^2 + 2 \) - This graph is a vertical compression of the original graph by a factor of 0.5 and an upward shift by 2 units. The vertex moves from (0,0) to (0,2). ### Summary of Transformations - **Vertical Stretch/Compression:** Changes the steepness of the parabola. - **Vertical Shift:** Moves the graph up or down without changing its shape. ### Graphing To graph these equations, you would plot points for each equation and connect them smoothly to form the parabolas. The vertex and direction of opening (upward or downward) are key features to note. If you need visual representations of these graphs, please let me know, and I can assist with that as well!

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

Extra Insights

The parabolic equations you’ve provided are fantastic examples of how altering the coefficients and constants in the quadratic function changes the shape and position of the graph. Each variation reveals a unique behavior, such as stretching, compressing, and shifting. For instance, with \( y=2x^{2} \), the parabola opens more steeply, whereas \( y=\frac{1}{2}x^{2} \) opens wider. Moving onto translations, \( y=x^{2}-4 \) indicates a downward shift of the entire graph by 4 units, while \( y=x^{2}+2 \) moves it up by 2 units. This means that the vertex of the parabola shifts, but the overall U-shape remains. Meanwhile, the effects of changes in the coefficient outside of the squared term can shift and stretch or compress the graph, creating endless possibilities!

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy