Which point is an \( x \)-intercept of the quadratic function \( f(x)=(x-8)(x+9) \) ? \( (0,8) \) \( (0,-8) \) \( (9,0) \) \( (-9,0) \)
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To find the \( x \)-intercepts of the function \( f(x) = (x-8)(x+9) \), we set the function equal to zero: \( (x-8)(x+9) = 0 \). This gives us two solutions: \( x - 8 = 0 \) or \( x + 9 = 0 \). Thus, the intercepts are \( x = 8 \) and \( x = -9 \). Therefore, the point \( (-9,0) \) is indeed an \( x \)-intercept! In quadratic functions, the \( x \)-intercepts are the solutions to the equation. They can often be found through factoring— just like in this case! It’s a nifty little method that helps you quickly find those intercepts without needing to graph the function. Always remember to check the solutions against the intercepts you have!