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Due pesi di 40 Ne 60 N sono appesi a una molla di costante elastica \( k=200 \mathrm{~N} / \mathrm{m} \). atcola la risultante delle forze applicate alla molla. l'allungamento della molla? [ \( 100 \mathrm{~N} ; 0 \)

Ask by Peters Dickson. in Italy
Mar 14,2025

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La risultante delle forze applicate alla molla è \( 100 \, \text{N} \) e l'allungamento della molla è \( 0.5 \, \text{m} \).

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La risultante delle forze applicate alla molla si ottiene sommando i pesi: \( 40 \, \text{N} + 60 \, \text{N} = 100 \, \text{N} \). Questo significa che la molla subirà un carico totale di 100 N. Per calcolare l'allungamento della molla si usa la legge di Hooke: \( F = k \cdot x \), quindi \( x = \frac{F}{k} = \frac{100 \, \text{N}}{200 \, \text{N/m}} = 0.5 \, \text{m} \). Quindi, l'allungamento della molla è di 0.5 metri!

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