\begin{tabular}{c|c}\( 7 x+2-2 \) & solve for \( x \) \\ \hline 0 & 4 \\ \hline 3 & -1 \\ \hline\end{tabular}

To solve the equation \( 7x + 2 - 2 = 0 \), we first simplify the equation: 1. Combine like terms: \[ 7x + 2 - 2 = 7x + 0 = 7x \] So, the equation simplifies to: \[ 7x = 0 \] 2. Now, divide both sides by 7 to isolate \( x \): \[ x = \frac{0}{7} = 0 \] Next, we will check the values provided in the table to see if they satisfy the equation \( 7x + 2 - 2 = 0 \). - For \( x = 4 \): \[ 7(4) + 2 - 2 = 28 + 2 - 2 = 28 \quad (\text{not } 0) \] - For \( x = 3 \): \[ 7(3) + 2 - 2 = 21 + 2 - 2 = 21 \quad (\text{not } 0) \] - For \( x = -1 \): \[ 7(-1) + 2 - 2 = -7 + 2 - 2 = -7 \quad (\text{not } 0) \] The only solution for the equation \( 7x + 2 - 2 = 0 \) is \( x = 0 \). The values \( 4 \), \( 3 \), and \(-1\) do not satisfy the equation. Thus, the solution is: \[ \boxed{0} \]