For what value of \( x \) is the following true? \[ \log (x+10)=\log x+\log 10 \] Your answer is: \[ x=\square \] You may enter the exact value or round to 4 decimal places. Next Question

1. Start with the given equation: \[ \log (x+10)=\log x+\log 10 \] 2. Use the logarithm property \(\log a + \log b = \log (ab)\) to combine the right-hand side: \[ \logx + \log 10 = \log(10x) \] Thus, the equation becomes: \[ \log (x+10) = \log (10x) \] 3. Since logarithm functions are one-to-one (assuming \(x>0\) and \(x+10>0\)), the arguments must be equal: \[ x + 10 = 10x \] 4. Solve for \(x\): \[ 10 = 10x - x = 9x \] \[ x = \frac{10}{9} \] 5. The solution is: \[ x=\frac{10}{9} \]