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VIII. \( 9 x-5=50 \) IX. \( 10 x+7=77 \) X. \( 11 x-8=63 \)

Ask by Brewer Moran. in Hong Kong
Feb 21,2025

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Answer

The solutions are: - VIII. \( x = \frac{55}{9} \) - IX. \( x = 7 \) - X. \( x = \frac{71}{11} \)

Solution

Let's solve each equation step by step. VIII. Solve 9x – 5 = 50  1. Add 5 to both sides:   9x – 5 + 5 = 50 + 5   9x = 55  2. Divide both sides by 9:   x = 55/9 IX. Solve 10x + 7 = 77  1. Subtract 7 from both sides:   10x + 7 – 7 = 77 – 7   10x = 70  2. Divide both sides by 10:   x = 70/10 = 7 X. Solve 11x – 8 = 63  1. Add 8 to both sides:   11x – 8 + 8 = 63 + 8   11x = 71  2. Divide both sides by 11:   x = 71/11 Thus, the solutions are: VIII. x = 55/9 IX. x = 7 X. x = 71/11

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Let's break these equations down! To solve the first equation \( 9x - 5 = 50 \), add 5 to both sides to get \( 9x = 55 \), then divide by 9 to find \( x = \frac{55}{9} \) or approximately 6.11. For the second equation \( 10x + 7 = 77 \), subtract 7 from both sides, resulting in \( 10x = 70 \). Dividing by 10 gives \( x = 7 \). Now for the third equation \( 11x - 8 = 63 \). Adding 8 to both sides yields \( 11x = 71 \), and dividing by 11 gives \( x = \frac{71}{11} \) or approximately 6.45. Perfect for your homework or just sharpening your math skills!

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