Suppose that the function \( f \) is defined on the interval \( [-2,2) \) as follows. \( f(x)=\left\{\begin{array}{ll}-2 & \text { if }-2 \leq x<-1 \\ -1 & \text { if }-1 \leq x<0 \\ 0 & \text { if } 0 \leq x<1 \\ 1 & \text { if } 1 \leq x<2\end{array}\right. \) Find \( f(-2), f(-0.75) \), and \( f(1) \) \( f(-2)=\square \) \( f(-0.75)=\square \)
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To find the values of \( f(-2) \), \( f(-0.75) \), and \( f(1) \) using the piecewise definition of the function: 1. For \( f(-2) \): Since \( -2 \) falls within the interval \( -2 \leq x < -1 \), according to the definition of \( f \), we have \( f(-2) = -2 \). 2. For \( f(-0.75) \): Here, \( -0.75 \) is included in the range \( -1 \leq x < 0 \), so from the piecewise definition, \( f(-0.75) = -1 \). 3. For \( f(1) \): The value \( 1 \) is in the range \( 1 \leq x < 2 \), therefore \( f(1) = 1 \). So, the final values are: \( f(-2)=-2 \) \( f(-0.75)=-1 \) \( f(1)=1 \)