\begin{tabular}{l} Which is the correct answer for \( 1 2 \longdiv { 0 . 6 } ? \) \\ A. 0.05 \\ B. 0.5 \\ C. 2 \\ D. 5 \\ E. 50 \\ \hline\end{tabular}

To solve \( 1 2 \longdiv { 0 . 6 } \), we can rewrite it as \( 12 \div 0.6 \). Dividing by a decimal can be tricky, but a little trick is to eliminate the decimal by multiplying both the dividend (12) and divisor (0.6) by 10, turning it into \( 120 \div 6 \). The answer is 20. However, since 20 isn't one of the choices provided, we should go back to the options and recognize that the original numbers can lead us to the equivalent value. Now, if we think of 0.6 as 6/10 or 3/5, we find that \( 12 \div (3/5) \) gives us \( 12 \times (5/3) = 20 \). While 20 seems out of place in the choices, if asked for values lesser than 20, notice that this method shows all options (A-E) are below this outcome. Thus, our careful deduction leads back to understanding option relevance! So when debating options, always reassess context and check for potential discrepancies in problem statement analysis.