10) \( 6 \times 21-12-7+24 \div 3-(33+12)= \)

To solve the expression \( 6 \times 21 - 12 - 7 + 24 \div 3 - (33 + 12) \), we need to follow the order of operations (PEMDAS/BODMAS). First, solve the multiplication and division: 1. \( 6 \times 21 = 126 \) 2. \( 24 \div 3 = 8 \) Substituting these into the expression, we get: \( 126 - 12 - 7 + 8 - (33 + 12) \) Now, simplify the expression inside the parentheses: \( 33 + 12 = 45 \) Now replace it back into the expression: \( 126 - 12 - 7 + 8 - 45 \) Now perform the addition and subtraction from left to right: 1. \( 126 - 12 = 114 \) 2. \( 114 - 7 = 107 \) 3. \( 107 + 8 = 115 \) 4. \( 115 - 45 = 70 \) Thus, the final answer is \( \boxed{70} \).