Question
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Answer
\( (x + 2y + 4z)^{2} = x^{2} + 4y^{2} + 16z^{2} + 4xy + 8xz + 16yz \)
Solution
Simplify the expression by following steps:
- step0: Evaluate the power:
\(\left(x+2y+4z\right)^{2}\)
- step1: Expand the expression:
\(x^{2}+\left(2y\right)^{2}+\left(4z\right)^{2}+2x\times 2y+2x\times 4z+2\times 2y\times 4z\)
- step2: Calculate:
\(x^{2}+4y^{2}+16z^{2}+4xy+8xz+16yz\)
\( (x + 2y + 4z)^{2} \) का प्रसार निम्नलिखित है:
\[
x^{2} + 4y^{2} + 16z^{2} + 4xy + 8xz + 16yz
\]
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Simplify this solution Beyond the Answer
प्रसार करने पर, \( (x + 2y + 4z)^2 \) का परिणाम कुछ इस प्रकार होगा: \[ = x^2 + (2y)^2 + (4z)^2 + 2(x)(2y) + 2(x)(4z) + 2(2y)(4z) \] अब इसे सरल करते हैं: \[ = x^2 + 4y^2 + 16z^2 + 4xy + 8xz + 16yz \] तो, \( (x + 2y + 4z)^2 \) का प्रसार \( x^2 + 4y^2 + 16z^2 + 4xy + 8xz + 16yz \) होगा।
