Solve this inequality: \( -\frac{1}{2} x-3 \leq-2.5 \) Step 1: Which property should be applied to isolate the variable term? Apply the \begin{tabular}{l} and \\ \( \qquad \begin{array}{l}\text { addition } \\ \text { multiplication } \\ \text { division }\end{array} \) \\ \hline\end{tabular}

To isolate the variable term in the inequality \(-\frac{1}{2} x - 3 \leq -2.5\), you should first apply the addition property. By adding 3 to both sides, you simplify the expression and focus on isolating the term with \(x\). This gives you \(-\frac{1}{2} x \leq 0.5\). After that, you'll want to apply the multiplication property to eliminate the fraction. Since you're multiplying by a negative number, remember to flip the inequality sign when you do this! If you multiply both sides by -2, you'll end up with \(x \geq -1\).