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Re-write the quadratic function below in Standard Form \[ y=2(x-2)^{2}-7 \]

Ask by Vaughan Burns. in the United States
Feb 19,2025

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Answer

The quadratic function in Standard Form is \( y = 2x^{2} - 8x + 1 \).

Solution

Rewrite the function by following steps: - step0: Rewrite the function: \(y=2x^{2}-8x+1\) The quadratic function \( y = 2(x-2)^{2} - 7 \) can be rewritten in Standard Form as: \[ y = 2x^{2} - 8x + 1 \]

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Mind Expander

To rewrite the quadratic function \( y=2(x-2)^{2}-7 \) in standard form, we need to expand the equation. Start by expanding \((x-2)^2\) to get: \[ y = 2((x^2 - 4x + 4)) - 7 \] Now distribute the 2: \[ y = 2x^2 - 8x + 8 - 7 \] Combine like terms: \[ y = 2x^2 - 8x + 1 \] So, the standard form of the quadratic function is: \[ y = 2x^2 - 8x + 1 \]

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