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Shooting a Basketball A basketball is shot at a \( 70^{\circ} \) angle with the horizontal direction with an initial speed of \( 10 \mathrm{~m} / \mathrm{sec} \). (a) Find the component form of the initial velocity,

Ask by Cox Bird. in the United States
Feb 20,2025

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The initial velocity has a horizontal component of approximately \( 6.333 \, \text{m/sec} \) and a vertical component of approximately \( 7.738 \, \text{m/sec} \).

Solution

To find the component form of the initial velocity, we need to break down the initial velocity into its horizontal and vertical components. Given: - Initial speed (\( v_0 \)) = \( 10 \, \text{m/sec} \) - Angle with the horizontal direction (\( \theta \)) = \( 70^\circ \) The horizontal component of the initial velocity (\( v_{0x} \)) is given by: \[ v_{0x} = v_0 \cos(\theta) \] The vertical component of the initial velocity (\( v_{0y} \)) is given by: \[ v_{0y} = v_0 \sin(\theta) \] Now, we can calculate the component form of the initial velocity using the given values. The horizontal component of the initial velocity is approximately \( 6.333 \, \text{m/sec} \). Now, let's calculate the vertical component of the initial velocity. The vertical component of the initial velocity is approximately \( 7.738 \, \text{m/sec} \). Therefore, the component form of the initial velocity is approximately \( 6.333 \, \text{m/sec} \) horizontally and \( 7.738 \, \text{m/sec} \) vertically.

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To find the component form of the initial velocity of the basketball, we can use trigonometric functions. The horizontal component \( v_x \) is calculated as \( v_x = v \cdot \cos(\theta) \), and the vertical component \( v_y \) is \( v_y = v \cdot \sin(\theta) \). With an initial speed \( v = 10 \, \text{m/s} \) and an angle \( \theta = 70^{\circ} \): \[ v_x = 10 \cdot \cos(70^{\circ}) \approx 3.42 \, \text{m/s} \] \[ v_y = 10 \cdot \sin(70^{\circ}) \approx 9.35 \, \text{m/s} \] Thus, the component form of the initial velocity is approximately \( (3.42, 9.35) \, \text{m/s} \). Engaging in basketball physics is both fun and enlightening! Did you know that the optimal angle for shooting a basketball is usually around \( 45^{\circ} \)? This allows for the perfect blend of horizontal distance and vertical height. However, shooting at \( 70^{\circ} \) can help players avoid defenders and create a better shooting arc, emphasizing the importance of angles in scoring! When shooting hoops, one common mistake players make is not considering their body positioning. Make sure to align your feet, shoulders, and arms in a straight line towards the basket for greater accuracy. Also, pay attention to your follow-through; it dramatically impacts how the ball leaves your hands. Practicing with proper mechanics makes a big difference in your shot’s success!

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