Find the zeros of the function. Enter the solutions from least to greatest. \( f(x)=(x+4)^{2}-25 \) lesser \( x=\square \) greater \( x=\square \)

To find the zeros of the function \( f(x) = (x+4)^{2} - 25 \), we start by setting the equation equal to zero: \[ (x+4)^{2} - 25 = 0 \] Next, we can rearrange the equation: \[ (x+4)^{2} = 25 \] Now, we take the square root of both sides: \[ x+4 = 5 \quad \text{or} \quad x+4 = -5 \] Solving these two equations gives: 1. \( x + 4 = 5 \) leads to \( x = 1 \) 2. \( x + 4 = -5 \) leads to \( x = -9 \) Thus, the zeros of the function are \( x = -9 \) and \( x = 1 \). lesser \( x = -9 \) greater \( x = 1 \)