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\#4 \( f(x)=x^{2}-12 x+11 \)

Ask by Reese Morgan. in the United States
Mar 16,2025

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The quadratic function \( f(x) = x^{2} - 12x + 11 \) can be factored as \( (x-1)(x-11) \). Its zeros are at \( x = 1 \) and \( x = 11 \). In vertex form, it is \( (x-6)^{2} - 25 \), with a vertex at \( (6, -25) \) and an axis of symmetry at \( x = 6 \).

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Beyond the Answer

Did you know that the function \( f(x) = x^2 - 12x + 11 \) represents a classic quadratic equation? Quadratics like this one always create a parabolic graph, and the shape is determined by the coefficient of \( x^2 \). In this case, since it's positive, the parabola opens upwards, which means it has a minimum point instead of a maximum! If you're looking to solve for the roots or intercepts of this equation, you can use the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} \), where \( a=1 \), \( b=-12 \), and \( c=11 \). Just plug in the numbers and let your calculator work its magic! You’ll find the points where the graph crosses the x-axis.

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