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QUESTION 5 A quadratic pattem has a second term equal to1, a third term equal \( 10-6 \) and a fifth term equal to -14 . 5.1 Calculate the second difference of this quadratic pattern. 5.2 Hence, or otherwise, calculate the first term of the pattern.

Ask by Adkins King. in South Africa
Mar 10,2025

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Tutor-Verified Answer

Answer

The second difference is -8, and the first term of the pattern is -10.

Solution

We assume the quadratic pattern has terms given by \[ a_n = An^2 + Bn + C. \] **Step 1. Write the equations for the known terms.** The pattern's given values are: - The second term: \( a_2 = 1 \) - The third term: \( a_3 = 10 - 6 = 4 \) - The fifth term: \( a_5 = -14 \) Using the general formula: 1. For \( n = 2 \): \[ 4A + 2B + C = 1 \] 2. For \( n = 3 \): \[ 9A + 3B + C = 4 \] 3. For \( n = 5 \): \[ 25A + 5B + C = -14 \] **Step 2. Eliminate \( C \) by subtracting equations.** Subtract the equation for \( a_2 \) from that for \( a_3 \): \[ (9A + 3B + C) - (4A + 2B + C) = 4 - 1 \] \[ 5A + B = 3 \quad \Longrightarrow \quad B = 3 - 5A. \] Subtract the equation for \( a_3 \) from that for \( a_5 \): \[ (25A + 5B + C) - (9A + 3B + C) = -14 - 4 \] \[ 16A + 2B = -18. \] Divide the entire equation by 2: \[ 8A + B = -9. \] **Step 3. Solve for \( A \) and \( B \).** Substitute \( B = 3 - 5A \) into \( 8A + B = -9 \): \[ 8A + (3 - 5A) = -9 \] \[ 3A + 3 = -9 \] \[ 3A = -12 \quad \Longrightarrow \quad A = -4. \] Now, substitute \( A = -4 \) back into \( B = 3 - 5A \): \[ B = 3 - 5(-4) = 3 + 20 = 23. \] **Step 4. Determine \( C \) using one of the equations.** Using the equation from \( a_2 \): \[ 4A + 2B + C = 1 \] Substitute \( A = -4 \) and \( B = 23 \): \[ 4(-4) + 2(23) + C = 1 \] \[ -16 + 46 + C = 1 \] \[ 30 + C = 1 \quad \Longrightarrow \quad C = 1 - 30 = -29. \] Thus, the quadratic pattern is \[ a_n = -4n^2 + 23n - 29. \] **Step 5. Calculate the second difference.** For any quadratic pattern, the second difference is constant and given by \[ \text{Second difference} = 2A. \] Substitute \( A = -4 \): \[ 2A = 2(-4) = -8. \] **Step 6. Calculate the first term of the pattern.** The first term is given by \( a_1 \): \[ a_1 = -4(1)^2 + 23(1) - 29 = -4 + 23 - 29. \] \[ a_1 = -10. \] **Final Answers:** 5.1 The second difference is \(-8\). 5.2 The first term of the pattern is \(-10\).

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The second difference of a quadratic sequence is constant and can be found by subtracting the first differences of the sequence. In this case, if we denote the terms of the quadratic sequence as \( a_1, a_2, a_3, a_4, ... \), we know \( a_2 = 1 \), \( a_3 = 10 - 6 = 4 \), and \( a_5 = -14 \). To find the second difference, we can determine the first differences: \( a_3 - a_2 = 4 - 1 = 3 \) and \( a_5 - a_4 \) will need \( a_4 \) first, which we can find from patterns. To obtain \( a_4 \), we can try different values based on our known terms, but if you explore how they relate, the second difference \(\Delta^2\) would ultimately be consistent, and from the pattern, we expect it to be \( -8 \). The first term can be calculated using the formula for a quadratic sequence, knowing that \( a_n = a + (n-1)d + \frac{(n-1)(n-2)}{2}c \), where \( c \) is the second difference. Plugging our values into this formula for \( n=1 \) allows us to solve for \( a_1 \). Given the consistent second difference, we can form equations to arrive at \( a_1 = 3 \).

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