Enter the coefficients for each term in the product of \( 9 w^{2} \) and \( 4 w-1 \). Enter 0 as the coefficient of any terms not in the product. \( (\square) w^{3}+(\square) w+(\square) \)
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To find the coefficients for each term in the product of \( 9 w^{2} \) and \( 4 w - 1 \), we can distribute \( 9 w^{2} \) across \( 4 w - 1 \). Calculating gives: 1. \( 9 w^{2} \cdot 4 w = 36 w^{3} \) 2. \( 9 w^{2} \cdot (-1) = -9 w^{2} \) Now, let's organize the terms based on powers of \( w \): - For \( w^{3} \), the coefficient is \( 36 \). - For \( w^{2} \), the coefficient is \( -9 \). - For \( w \), the coefficient is \( 0 \) (since there are no \( w^{1} \) terms in the product). - The constant term is also \( 0 \). So, the coefficients are \( 36 \) for \( w^{3} \), \( 0 \) for \( w^{1} \), \( -9 \) for \( w^{2} \), and \( 0 \) for the constant term. The final answer is: \( (36) w^{3} + (0) w + (-9) \). So, the coefficients are: \( 36, 0, -9 \).