Solve \( \frac{x-1}{3}-\frac{x+2}{4}=2 \) Your Answer: Answer
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The Deep Dive
To solve the equation \( \frac{x-1}{3}-\frac{x+2}{4}=2 \), first, we need to find a common denominator for the fractions. The least common multiple of 3 and 4 is 12. Rewriting the equation with a common denominator, we have: \[ \frac{4(x-1)}{12} - \frac{3(x+2)}{12} = 2 \] This simplifies to: \[ \frac{4(x-1) - 3(x+2)}{12} = 2 \] Now, combine the numerators: \[ 4(x-1) - 3(x+2) = 4x - 4 - 3x - 6 = x - 10 \] So we rewrite the equation as: \[ \frac{x - 10}{12} = 2 \] To eliminate the fraction, multiply both sides by 12: \[ x - 10 = 24 \] Adding 10 to both sides gives: \[ x = 34 \] Thus, the solution to the equation is \( x = 34 \).