Use long division to calc \( 76593 \div 45 \)

1. **Divide the first part of the dividend:** Consider the first two digits of \(76593\), which is \(76\). Since \[ 45 \times 1 = 45 \quad \text{and} \quad 45 \times 2 = 90 \quad (90 > 76), \] we see that \(45\) fits into \(76\) exactly \(1\) time. - Multiply: \(1 \times 45 = 45\) - Subtract: \(76 - 45 = 31\) 2. **Bring down the next digit:** Bring down the next digit \(5\) to the remainder \(31\) to form \(315\). Now, determine how many times \(45\) goes into \(315\): \[ 45 \times 7 = 315, \] so it goes in \(7\) times exactly. - Subtract: \(315 - 315 = 0\) 3. **Bring down the next digit:** Bring down the next digit, \(9\). Since \(45\) does not fit into \(9\) (because \(9 < 45\)), we record a \(0\) in the quotient for this place. - Write \(0\) in the quotient. - The remainder remains \(9\). 4. **Bring down the final digit:** Bring down the last digit, \(3\), to the remainder \(9\), forming \(93\). Determine how many times \(45\) goes into \(93\): \[ 45 \times 2 = 90 \quad \text{and} \quad 45 \times 3 = 135 \quad (135 > 93), \] so \(45\) goes \(2\) times into \(93\). - Multiply: \(2 \times 45 = 90\) - Subtract: \(93 - 90 = 3\) 5. **Conclusion:** The quotient from the long division is formed by the digits obtained in each step, which gives \(1702\). The final remainder is \(3\). Thus, \[ 76593 \div 45 = 1702 \text{ with a remainder of } 3. \]