One line passes through the points \( (2,1) \) and \( (5,7) \). Another line passes through points \( (-3,8) \) and \( (8,3) \). Are the lines parallel, perpendicular, or neither? Choose 1 answer: (A) Parallel (B) Perpendicular (C) Neither

The slope of the line that passes through the points \( (2,1) \) and \( (5,7) \) is given by the formula \( m = \frac{y_2-y_1}{x_2-x_1} \). This calculates to \( m = \frac{7-1}{5-2} = \frac{6}{3} = 2 \). For the line that passes through \( (-3,8) \) and \( (8,3) \), the slope is \( m = \frac{3-8}{8-(-3)} = \frac{-5}{11} \). Since the product of the slopes \( 2 \times \left(-\frac{5}{11}\right) \) is not \(-1\) (indicative of perpendicular lines) and they have different slopes, the lines are neither parallel nor perpendicular. The correct answer is (C) Neither.