Question
Subtract. \[ \frac{7}{x}-\frac{6}{x+1} \] Simplify your answer as much as possible. \( \square \)
Ask by Phillips Hill. in the United States
Feb 26,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The simplified form is \( \frac{x+7}{x^{2}+x} \).
Solution
Calculate or simplify the expression \( \frac{7}{x}-\frac{6}{x+1} \).
Simplify the expression by following steps:
- step0: Solution:
\(\frac{7}{x}-\frac{6}{x+1}\)
- step1: Reduce fractions to a common denominator:
\(\frac{7\left(x+1\right)}{x\left(x+1\right)}-\frac{6x}{\left(x+1\right)x}\)
- step2: Rewrite the expression:
\(\frac{7\left(x+1\right)}{x\left(x+1\right)}-\frac{6x}{x\left(x+1\right)}\)
- step3: Transform the expression:
\(\frac{7\left(x+1\right)-6x}{x\left(x+1\right)}\)
- step4: Multiply the terms:
\(\frac{7x+7-6x}{x\left(x+1\right)}\)
- step5: Subtract the terms:
\(\frac{x+7}{x\left(x+1\right)}\)
- step6: Multiply the terms:
\(\frac{x+7}{x^{2}+x}\)
The simplified form of the expression \( \frac{7}{x}-\frac{6}{x+1} \) is \( \frac{x+7}{x^{2}+x} \).
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Mind Expander
To subtract the fractions \( \frac{7}{x} - \frac{6}{x+1} \), first, we need a common denominator, which is \( x(x+1) \). Now, rewrite each fraction: \[ \frac{7}{x} = \frac{7(x+1)}{x(x+1)} = \frac{7x + 7}{x(x+1)} \] \[ \frac{6}{x+1} = \frac{6x}{x(x+1)} \] Subtract the two fractions: \[ \frac{7x + 7}{x(x+1)} - \frac{6x}{x(x+1)} = \frac{(7x + 7 - 6x)}{x(x+1)} = \frac{x + 7}{x(x+1)} \] So the simplified answer is: \[ \frac{x + 7}{x(x+1)} \]