Subtract. \[ \frac{7}{x}-\frac{6}{x+1} \] Simplify your answer as much as possible. \( \square \)

To subtract the fractions \( \frac{7}{x} - \frac{6}{x+1} \), first, we need a common denominator, which is \( x(x+1) \). Now, rewrite each fraction: \[ \frac{7}{x} = \frac{7(x+1)}{x(x+1)} = \frac{7x + 7}{x(x+1)} \] \[ \frac{6}{x+1} = \frac{6x}{x(x+1)} \] Subtract the two fractions: \[ \frac{7x + 7}{x(x+1)} - \frac{6x}{x(x+1)} = \frac{(7x + 7 - 6x)}{x(x+1)} = \frac{x + 7}{x(x+1)} \] So the simplified answer is: \[ \frac{x + 7}{x(x+1)} \]