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Write an explicit formula for \( a_{n} \), the \( n^{\text {th }} \) term of the sequence \( 25,33,41, \ldots \) Answer Attempt 1 out of 3 \( a_{n}=\square \)

Ask by Cox Hilton. in the United States
Mar 14,2025

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Answer

The explicit formula for the \( n^{\text{th}} \) term of the sequence is \( a_{n} = 8n + 17 \).

Solution

To find the explicit formula for the \( n^{\text{th}} \) term of the sequence \( 25, 33, 41, \ldots \), we first need to identify the pattern in the sequence. 1. **Identify the first term and the common difference:** - The first term \( a_1 = 25 \). - The second term \( a_2 = 33 \). - The third term \( a_3 = 41 \). 2. **Calculate the common difference:** - \( a_2 - a_1 = 33 - 25 = 8 \) - \( a_3 - a_2 = 41 - 33 = 8 \) The common difference \( d = 8 \). 3. **Use the formula for the \( n^{\text{th}} \) term of an arithmetic sequence:** The formula for the \( n^{\text{th}} \) term of an arithmetic sequence is given by: \[ a_n = a_1 + (n - 1) \cdot d \] 4. **Substituting the known values:** - \( a_1 = 25 \) - \( d = 8 \) Therefore, the formula becomes: \[ a_n = 25 + (n - 1) \cdot 8 \] 5. **Simplifying the formula:** \[ a_n = 25 + 8n - 8 = 8n + 17 \] Thus, the explicit formula for the \( n^{\text{th}} \) term of the sequence is: \[ a_n = 8n + 17 \] So, the answer is: \[ a_{n} = 8n + 17 \]

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The Deep Dive

To find the explicit formula for the sequence \( 25, 33, 41, \ldots \), let's start by identifying the pattern. The first term is \( 25 \), and the difference between consecutive terms is \( 8 \) (i.e., \( 33 - 25 = 8 \) and \( 41 - 33 = 8 \)). This indicates it is an arithmetic sequence with a common difference of \( 8 \). Following the formula for the \( n^{\text{th}} \) term of an arithmetic sequence, \( a_n = a_1 + (n - 1)d \), where \( a_1 \) is the first term and \( d \) is the common difference, we have: \[ a_n = 25 + (n - 1) \cdot 8 \] Simplifying this, we get: \[ a_n = 25 + 8n - 8 = 8n + 17 \] So the explicit formula for the sequence is: \[ a_n = 8n + 17 \]

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