Write an explicit formula for \( a_{n} \), the \( n^{\text {th }} \) term of the sequence \( 25,33,41, \ldots \) Answer Attempt 1 out of 3 \( a_{n}=\square \)
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The Deep Dive
To find the explicit formula for the sequence \( 25, 33, 41, \ldots \), let's start by identifying the pattern. The first term is \( 25 \), and the difference between consecutive terms is \( 8 \) (i.e., \( 33 - 25 = 8 \) and \( 41 - 33 = 8 \)). This indicates it is an arithmetic sequence with a common difference of \( 8 \). Following the formula for the \( n^{\text{th}} \) term of an arithmetic sequence, \( a_n = a_1 + (n - 1)d \), where \( a_1 \) is the first term and \( d \) is the common difference, we have: \[ a_n = 25 + (n - 1) \cdot 8 \] Simplifying this, we get: \[ a_n = 25 + 8n - 8 = 8n + 17 \] So the explicit formula for the sequence is: \[ a_n = 8n + 17 \]