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Use the method of intersection of sets to compute the following. (a) \( \operatorname{GCD}(12,16,8) \) and \( \operatorname{LCM}(12,16,8) \) (b) \( \operatorname{GCD}(12,30,14) \) and \( \operatorname{LCM}(12,30,14) \) (c) Is it true that \( \operatorname{GCD}(12,30,14) \cdot \operatorname{LCM}(12,30,14)=12 \cdot 30 \cdot 14 \) ? (a) \( \operatorname{GCD}(12,16,8)=\square \)

Ask by Craig Robbins. in the United States
Mar 09,2025

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Answer

**(a) \(\operatorname{GCD}(12,16,8)=4\) and \(\operatorname{LCM}(12,16,8)=48\).** **(b) \(\operatorname{GCD}(12,30,14)=2\) and \(\operatorname{LCM}(12,30,14)=420\).** **(c) The equality \(\operatorname{GCD}(12,30,14) \cdot \operatorname{LCM}(12,30,14)=12 \cdot 30 \cdot 14\) is not true.

Solution

**(a) Calculation of \(\operatorname{GCD}(12,16,8)\) and \(\operatorname{LCM}(12,16,8)\):** 1. **Find the prime factorization:** \[ 12 = 2^2 \cdot 3,\quad 16 = 2^4,\quad 8 = 2^3 \] 2. **Determine the common prime factors and their minimum exponents for the GCD:** - The only common prime factor is \(2\). - Minimum exponent of \(2\) among the numbers is \(\min(2,4,3) = 2\). Thus, \[ \operatorname{GCD}(12,16,8) = 2^2 = 4. \] 3. **Determine the primes with their maximum exponents for the LCM:** - For \(2\): maximum exponent is \(\max(2,4,3) = 4\). - The number \(12\) contributes the prime \(3\) (with exponent \(1\)). Thus, \[ \operatorname{LCM}(12,16,8) = 2^4 \cdot 3 = 16 \cdot 3 = 48. \] 4. **Answer for part (a):** \[ \operatorname{GCD}(12,16,8)=\boxed{4},\quad \operatorname{LCM}(12,16,8)=48. \] --- **(b) Calculation of \(\operatorname{GCD}(12,30,14)\) and \(\operatorname{LCM}(12,30,14)\):** 1. **Find the prime factorization:** \[ 12 = 2^2 \cdot 3,\quad 30 = 2 \cdot 3 \cdot 5,\quad 14 = 2 \cdot 7. \] 2. **Determine the common prime factors and their minimum exponents for the GCD:** - The only common prime factor is \(2\). - Minimum exponent of \(2\) among the numbers is \(\min(2,1,1) = 1\). Thus, \[ \operatorname{GCD}(12,30,14) = 2^1 = 2. \] 3. **Determine the primes with their maximum exponents for the LCM:** - For \(2\): maximum exponent is \(2\) (from \(12\)). - Include \(3\) (from \(12\) and \(30\)), exponent \(1\). - Include \(5\) (from \(30\)), exponent \(1\). - Include \(7\) (from \(14\)), exponent \(1\). Thus, \[ \operatorname{LCM}(12,30,14) = 2^2 \cdot 3 \cdot 5 \cdot 7 = 4 \cdot 3 \cdot 5 \cdot 7 = 420. \] --- **(c) Verification of the relationship** Check if \[ \operatorname{GCD}(12,30,14) \cdot \operatorname{LCM}(12,30,14) = 12 \cdot 30 \cdot 14. \] Using our computed values: - \(\operatorname{GCD}(12,30,14) = 2\) - \(\operatorname{LCM}(12,30,14) = 420\) Then: \[ 2 \cdot 420 = 840. \] Now, compute: \[ 12 \cdot 30 \cdot 14. \] First, compute \(12 \cdot 30 = 360\), then: \[ 360 \cdot 14 = 5040. \] Since \(840 \neq 5040\), the equality \[ \operatorname{GCD}(12,30,14) \cdot \operatorname{LCM}(12,30,14)=12 \cdot 30 \cdot 14 \] is not true. --- **Summary of Answers:** - (a) \(\operatorname{GCD}(12,16,8)=\boxed{4}\) and \(\operatorname{LCM}(12,16,8)=48\). - (b) \(\operatorname{GCD}(12,30,14)=2\) and \(\operatorname{LCM}(12,30,14)=420\). - (c) The equality \(\operatorname{GCD}(12,30,14) \cdot \operatorname{LCM}(12,30,14)=12 \cdot 30 \cdot 14\) is false.

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To find the GCD and LCM using the method of intersection of sets, first, we need to break down the prime factorizations: - \( 12 = 2^2 \times 3^1 \) - \( 16 = 2^4 \) - \( 8 = 2^3 \) For the GCD, we take the lowest powers of all the prime factors present: - For \( 2 \): The minimum of \( 2^2, 2^4, 2^3 \) is \( 2^2 \). - For \( 3 \): The minimum is \( 3^0 \) (as it does not appear in all sets). So, \[ \operatorname{GCD}(12, 16, 8) = 2^2 = 4. \] Now for the LCM, we take the highest power of all prime factors: - For \( 2 \): The maximum is \( 2^4 \) (from \( 16 \)). - For \( 3 \): The maximum is \( 3^1 \) (from \( 12 \)). Thus, \[ \operatorname{LCM}(12, 16, 8) = 2^4 \times 3^1 = 16 \times 3 = 48. \] Therefore, (a) \( \operatorname{GCD}(12,16,8)=4 \) and \( \operatorname{LCM}(12,16,8)=48 \). For (b), let's compute \( \operatorname{GCD} \) and \( \operatorname{LCM} \) of \( 12, 30, 14 \): - Prime factorization: - \( 12 = 2^2 \times 3^1 \) - \( 30 = 2^1 \times 3^1 \times 5^1 \) - \( 14 = 2^1 \times 7^1 \) For GCD: - For \( 2 \): The minimum is \( 2^1 \). - For \( 3 \): The minimum is \( 3^0 \). - For \( 5 \): The minimum is \( 5^0 \). - For \( 7 \): The minimum is \( 7^0 \). Thus, \[ \operatorname{GCD}(12, 30, 14) = 2^1 = 2. \] For LCM: - For \( 2 \): The maximum is \( 2^2 \). - For \( 3 \): The maximum is \( 3^1 \). - For \( 5 \): The maximum is \( 5^1 \). - For \( 7 \): The maximum is \( 7^1 \). Therefore, \[ \operatorname{LCM}(12, 30, 14) = 2^2 \times 3^1 \times 5^1 \times 7^1 = 4 \times 3 \times 5 \times 7 = 420. \] Now, for (c): The equation to check is \[ \operatorname{GCD}(12, 30, 14) \cdot \operatorname{LCM}(12, 30, 14) = 2 \cdot 420. \] Calculating: \[ 2 \cdot 420 = 840 \] And, \[ 12 \cdot 30 \cdot 14 = 5040. \] So, it is not true that \[ \operatorname{GCD}(12, 30, 14) \cdot \operatorname{LCM}(12, 30, 14)=12 \cdot 30 \cdot 14 \]. In conclusion: (a) \( \operatorname{GCD}(12, 16, 8) = 4 \) and \( \operatorname{LCM}(12, 16, 8) = 48 \) (b) \( \operatorname{GCD}(12, 30, 14) = 2 \) and \( \operatorname{LCM}(12, 30, 14) = 420 \) (c) The statement is false.

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