Use the method of intersection of sets to compute the following. (a) \( \operatorname{GCD}(12,16,8) \) and \( \operatorname{LCM}(12,16,8) \) (b) \( \operatorname{GCD}(12,30,14) \) and \( \operatorname{LCM}(12,30,14) \) (c) Is it true that \( \operatorname{GCD}(12,30,14) \cdot \operatorname{LCM}(12,30,14)=12 \cdot 30 \cdot 14 \) ? (a) \( \operatorname{GCD}(12,16,8)=\square \)
Upstudy AI Solution
Answer
Solution
Answered by UpStudy AI and reviewed by a Professional Tutor


Bonus Knowledge
To find the GCD and LCM using the method of intersection of sets, first, we need to break down the prime factorizations: - \( 12 = 2^2 \times 3^1 \) - \( 16 = 2^4 \) - \( 8 = 2^3 \) For the GCD, we take the lowest powers of all the prime factors present: - For \( 2 \): The minimum of \( 2^2, 2^4, 2^3 \) is \( 2^2 \). - For \( 3 \): The minimum is \( 3^0 \) (as it does not appear in all sets). So, \[ \operatorname{GCD}(12, 16, 8) = 2^2 = 4. \] Now for the LCM, we take the highest power of all prime factors: - For \( 2 \): The maximum is \( 2^4 \) (from \( 16 \)). - For \( 3 \): The maximum is \( 3^1 \) (from \( 12 \)). Thus, \[ \operatorname{LCM}(12, 16, 8) = 2^4 \times 3^1 = 16 \times 3 = 48. \] Therefore, (a) \( \operatorname{GCD}(12,16,8)=4 \) and \( \operatorname{LCM}(12,16,8)=48 \). For (b), let's compute \( \operatorname{GCD} \) and \( \operatorname{LCM} \) of \( 12, 30, 14 \): - Prime factorization: - \( 12 = 2^2 \times 3^1 \) - \( 30 = 2^1 \times 3^1 \times 5^1 \) - \( 14 = 2^1 \times 7^1 \) For GCD: - For \( 2 \): The minimum is \( 2^1 \). - For \( 3 \): The minimum is \( 3^0 \). - For \( 5 \): The minimum is \( 5^0 \). - For \( 7 \): The minimum is \( 7^0 \). Thus, \[ \operatorname{GCD}(12, 30, 14) = 2^1 = 2. \] For LCM: - For \( 2 \): The maximum is \( 2^2 \). - For \( 3 \): The maximum is \( 3^1 \). - For \( 5 \): The maximum is \( 5^1 \). - For \( 7 \): The maximum is \( 7^1 \). Therefore, \[ \operatorname{LCM}(12, 30, 14) = 2^2 \times 3^1 \times 5^1 \times 7^1 = 4 \times 3 \times 5 \times 7 = 420. \] Now, for (c): The equation to check is \[ \operatorname{GCD}(12, 30, 14) \cdot \operatorname{LCM}(12, 30, 14) = 2 \cdot 420. \] Calculating: \[ 2 \cdot 420 = 840 \] And, \[ 12 \cdot 30 \cdot 14 = 5040. \] So, it is not true that \[ \operatorname{GCD}(12, 30, 14) \cdot \operatorname{LCM}(12, 30, 14)=12 \cdot 30 \cdot 14 \]. In conclusion: (a) \( \operatorname{GCD}(12, 16, 8) = 4 \) and \( \operatorname{LCM}(12, 16, 8) = 48 \) (b) \( \operatorname{GCD}(12, 30, 14) = 2 \) and \( \operatorname{LCM}(12, 30, 14) = 420 \) (c) The statement is false.