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\begin{tabular}{l|l|} Each & \( \begin{array}{l}\text { A bowling alley charges } \$ 185 \text { per } \\ \text { hour for parties. How many dollars } \\ \text { would a } 2.5 \text {-hour party cost? }\end{array} \) \\ \( \begin{array}{ll}\text { (A) } \$ 462.50 & \text { (C) } \$ 3,700.00 \\ \text { (B) } \$ 370.00 & \text { (D) } \$ 4,625.00\end{array} \)\end{tabular}

Ask by Chadwick Lyons. in the United States
Mar 16,2025

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Tutor-Verified Answer

Answer

A \( 2.5 \)-hour party would cost \$462.50.

Solution

1. The cost per hour for a party is given as \( \$185 \). 2. For a \( 2.5 \)-hour party, the total cost is calculated by multiplying the hourly rate by the number of hours: \[ \text{Total cost} = 185 \times 2.5 \] 3. Multiply: \[ 185 \times 2.5 = 185 \times \frac{5}{2} = \frac{925}{2} = 462.50 \] 4. Therefore, the total cost for a \( 2.5 \)-hour party is \(\$462.50\). The answer is \( \$462.50 \).

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To find the total cost for a 2.5-hour party at the bowling alley, simply multiply the hourly rate by the duration. So, you would do \( 185 \times 2.5 \), which equals \( 462.50 \). This means the total cost for the party would be \$462.50! If you're ever unsure about these calculations, remember the powers of multiplication! A common mistake is forgetting to convert things properly – in this case, just make sure both numbers are in the same measurement (hours) before multiplying. Keep those decimal points straight, and you'll never go wrong!

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