Simplify the expression below if \( a=-2 \) and \( b=5 \). \[ 7-\frac{5 a-2\left(3 a^{3} b\right)}{|a b-5|} \]
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First, we need to plug in the values \( a = -2 \) and \( b = 5 \) into the expression: \[ 7 - \frac{5(-2) - 2\left(3(-2)^{3}(5)\right)}{|(-2)(5) - 5|} \] Next, we calculate each component starting with \( |a b - 5| \): \[ ab = (-2)(5) = -10 \quad \Rightarrow \quad |ab - 5| = |-10 - 5| = |-15| = 15 \] Now let’s calculate \( 5a \): \[ 5a = 5(-2) = -10 \] Next, calculate \( 3a^3b \): \[ (-2)^3 = -8 \quad \Rightarrow \quad 3(-8)(5) = -120 \] Thus, \( 2(3a^3b) = 2(-120) = -240 \). Now we substitute these values back into the expression: \[ 7 - \frac{-10 - (-240)}{15} \] This simplifies to: \[ 7 - \frac{-10 + 240}{15} = 7 - \frac{230}{15} \] Next, simplify \( \frac{230}{15} \): \[ \frac{230}{15} = \frac{46}{3} \] Now substituting this into the expression gives us: \[ 7 - \frac{46}{3} \] To perform the subtraction, we convert 7 into a fraction: \[ 7 = \frac{21}{3} \] Now, we can perform the subtraction: \[ \frac{21}{3} - \frac{46}{3} = \frac{21 - 46}{3} = \frac{-25}{3} \] Thus, the simplified expression is: \[ \boxed{\frac{-25}{3}} \]