Solve the equation \( p^{2}-8 p+12=0 \) by factoring. \( p=\square \) If there is more than 1 solution, separate the values with a comma. \( > \) Next Question

1. Start with the equation: \[ p^2 - 8p + 12 = 0 \] 2. Look for two numbers that multiply to \(12\) and add to \(-8\). These numbers are \(-2\) and \(-6\) because: \[ (-2) \times (-6) = 12 \quad \text{and} \quad (-2) + (-6) = -8 \] 3. Rewrite the quadratic as a product of factors: \[ (p - 2)(p - 6) = 0 \] 4. Use the Zero Product Property. Set each factor equal to zero: - \( p - 2 = 0 \) which gives \( p = 2 \) - \( p - 6 = 0 \) which gives \( p = 6 \) 5. The solutions are: \[ p = 2, 6 \]